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Linear functional. Matrix representation. Dual space, conjugate space, adjoint space. Basis for dual space. Annihilator. Transpose of a linear mapping.



Def. Functional. Let V be an abstract vector space over a field F. A functional T is a function T:V ole.gif F that assigns a number from field F to each vector x ε V.



Def. Linear functional. A functional T is linear if

 

                                    T(av1 + bv2) = aTv1 + bTv2

 

for all vectors v1 and v2 and scalars a and b.


Examples.


1. Let V be the vector space of polynomials in t over R, the field of reals. Let T:V ole1.gif R be the integral operator defined by


              ole2.gif   


This integral effects a linear mapping from the space of polynomials to the field of reals and hence T is a linear functional.


2. Let V be the vector space of n-square matrices over F. Let T:V ole3.gif R be the trace mapping


                                    T(A) = ole4.gif where matrix A = ( ole5.gif )


That is, T assigns to a matrix A the sum of its diagonal elements. This mapping can be shown to be linear and hence T is a linear functional.


3. Let πi:Rn ole6.gif R be the i-th projection mapping i.e. for any vector X = (a1, a2, ..... , an) ε Rn, πi = ai, the i-th coordinate of X. This mapping is linear and πi is a linear functional on Rn.


 

The domain V of a linear functional T: V ole7.gif F can be either infinite dimensional or finite dimensional. We will consider here only linear functionals in which the domain V is finite dimensional.


 

Matrix representation of a linear functional whose domain is finite dimensional. Any linear mapping from one finite dimensional abstract vector space to another is represented by a matrix. A linear mapping from an n-dimensional vector space over a field F to an m-dimensional vector space over F is represented by an mxn matrix.over F. A linear functional T: V ole8.gif F whose domain V is finite dimensional is a linear mapping from an n-dimensional vector space to a 1-dimensional vector space and is represented by a 1xn matrix i.e. an n-element row vector. The matrix representation of the mapping is


                                      T(v) = Av


where v is an n-element coordinate vector and A is a 1xn matrix representation of T. Thus the linear functional has the form


                 ole9.gif



or

 

               T(v) = ole10.gif





Dual Space. If V is some abstract vector space over a field F, then the dual space of V is the vector space V* consisting of all linear functionals with domain V and range contained in F. The dual space V*, of a space V, is the vector space Hom (V,F). Linear functionals whose domain is finite dimensional and of dimension n are represented by 1xn matrices and dual space [ Hom (V,F) ] corresponds to the set of all 1xn matrices over F. If V is of dimension n then the dual space has dimension n.


Syn. conjugate space, adjoint space





Example. Let V be column space consisting of all n-element column vectors over R. Let

 T: V ole11.gif F be


                                                T(v) = [ ole12.gif ]v


where ole13.gif are real numbers and v is any element in V. The row vector [ ole14.gif ] can be viewed as a linear operator operating on vectors in V. It is a linear functional which maps elements of V into field R. The dual space V* of V is then the vector space of all n-element row vectors. Thus row space is the dual space of column space V.




Basis for Dual Space. Suppose V is some abstract vector space of dimension n over a field F. Suppose { ole15.gif } is a basis for V. Then a basis for the dual space V* of V is the set of n linear functionals ole16.gif ole17.gif V* defined by


             ole18.gif


   ole19.gif


where i = 1,n; j = 1,n, giving the following n mappings:



             ole20.gif mapping: v1 ole21.gif 1, v2 ole22.gif 0, v3 ole23.gif 0, ..... , vn ole24.gif 0

             ole25.gif mapping: v1 ole26.gif 0, v2 ole27.gif 1, v3 ole28.gif 0, ..... , vn ole29.gif 0

                 ...........................................................................

             ole30.gif  mapping: v1 ole31.gif 0, v2 ole32.gif 0, v3 ole33.gif 0, ..... , vn ole34.gif 1



The basis { ole35.gif } is called the basis dual to { ole36.gif } or the dual basis. There are infinitely many possible bases for V and each basis has a dual basis as defined above.


See


Hom(V,W). Vector space of all mxn matrices.

Vector space Hom(V,W)



Theorem 1. Let { ole37.gif } be a basis for V and let { ole38.gif } be the basis of V* (i.e. dual basis). Then for any vector u ole39.gif V,


                         ole40.gif


and for any linear functional ole41.gif ole42.gif V*


                        ole43.gif




Thus we see that the coordinates of u are ole44.gif and the coordinates of σ

are ole45.gif .





Annihilator. Let W be a subset (not necessarily a subspace) of a vector space V. A linear functional ole46.gif ole47.gif V* is called an annihilator of W if ole48.gif (w) = 0 for every w ole49.gif W. The set of all such mappings, denoted by W0 and called the annihilator of W, is a subspace of V*.

  


Example. Pass a line through the origin of an x-y-z Cartesian coordinate system and label it L. Let W be the set of all vectors in line L. Pass a plane through the origin of the coordinate system perpendicular to line L and label it K. Let S represent the set of all vectors in plane K. Then S is an annihilator of W. Why? If s is any vector in S and w is any vector in W then the dot product s∙w = 0. The vector s can be viewed as a linear operator (linear functional) mapping the vectors of W into the field of reals and it maps all the elements of W into zero. By the same logic W is an annihilator of S. So the annihilator W0 of W is the set S and the annihilator S0 of the set S is the set W.

 

Theorem 2. Suppose V has finite dimension and W is a subspace of V. Then


1)        dimW + dim W0 = dim V

 

and

 

2)        W00 = W


 


ole50.gif

Transpose of a linear mapping. Let T:V ole51.gif U be an arbitrary linear mapping from a vector space V into a vector space U. Now for any linear functional ω ε U*, the composition mapping ω ole52.gif T is a linear mapping from V into F. See Fig. 1. Thus ω ole53.gif T ε V*. We thus have a one-to-one correspondence between ω ε U* and ω ole54.gif T ε V*. The linear mapping


            T t (ω) = ω ole55.gif T


that maps ω ε U* into ω ole56.gif T ε V* is called the transpose of T.


Thus [T t (ω)]v = ω(Tv) for every v ε V.


In summary, if T is a linear mapping from V into U, then T t is a linear mapping from U* into V*:


             ole57.gif   



Theorem 3. Let T:V ole58.gif U be linear, and let A be the matrix representation of T relative to bases {vi} of V and {ui} of U. Then the transpose matrix At is the matrix representation of T t:U* ole59.gif V* relative to the bases dual to {ui} and {vi}.                                                                 





References

  Lipschutz. Linear Algebra. p. 249-251

  Taylor. Introduction to Functional Analysis. p. 33


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