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Linear functional. Matrix representation. Dual space, conjugate space, adjoint space. Basis for dual space. Annihilator. Transpose of a linear mapping.
Def. Functional. Let V be an abstract vector space over a field F. A functional T is a
function T:V
F that assigns a number from field F to each vector x ε V.
Def. Linear functional. A functional T is linear if
T(av1 + bv2) = aTv1 + bTv2
for all vectors v1 and v2 and scalars a and b.
Examples.
1. Let V be the vector space of polynomials in t over R, the field of reals. Let T:V
R be the
integral operator defined by
This integral effects a linear mapping from the space of polynomials to the field of reals and hence T is a linear functional.
2. Let V be the vector space of n-square matrices over F. Let T:V
R be the trace mapping
T(A) =
where matrix A = (
)
That is, T assigns to a matrix A the sum of its diagonal elements. This mapping can be shown to be linear and hence T is a linear functional.
3. Let πi:Rn
R be the i-th projection mapping i.e. for any vector X = (a1, a2, ..... , an) ε Rn, πi =
ai, the i-th coordinate of X. This mapping is linear and πi is a linear functional on Rn.
The domain V of a linear functional T: V
F can be either infinite dimensional or finite
dimensional. We will consider here only linear functionals in which the domain V is finite
dimensional.
Matrix representation of a linear functional whose domain is finite
dimensional. Any linear mapping from one finite dimensional abstract vector space to another
is represented by a matrix. A linear mapping from an n-dimensional vector space over a field F
to an m-dimensional vector space over F is represented by an mxn matrix.over F. A linear
functional T: V
F whose domain V is finite dimensional is a linear mapping from an n-dimensional vector space to a 1-dimensional vector space and is represented by a 1xn matrix i.e.
an n-element row vector. The matrix representation of the mapping is
T(v) = Av
where v is an n-element coordinate vector and A is a 1xn matrix representation of T. Thus the linear functional has the form
or
T(v) =
Dual Space. If V is some abstract vector space over a field F, then the dual space of V is the vector space V* consisting of all linear functionals with domain V and range contained in F. The dual space V*, of a space V, is the vector space Hom (V,F). Linear functionals whose domain is finite dimensional and of dimension n are represented by 1xn matrices and dual space [ Hom (V,F) ] corresponds to the set of all 1xn matrices over F. If V is of dimension n then the dual space has dimension n.
Syn. conjugate space, adjoint space
Example. Let V be column space consisting of all n-element column vectors over R. Let
T: V
F be
T(v) = [
]v
where
are real numbers and v is any element in V. The row vector
[
] can be viewed as a linear operator operating on vectors in V. It is a linear
functional which maps elements of V into field R. The dual space V* of V is then the vector
space of all n-element row vectors. Thus row space is the dual space of column space V.
Basis for Dual Space. Suppose V is some abstract vector space of dimension n over a field
F. Suppose {
} is a basis for V. Then a basis for the dual space V* of V is the set
of n linear functionals
V* defined by
where i = 1,n; j = 1,n, giving the following n mappings:
mapping: v1
1, v2
0, v3
0, ..... , vn
0
mapping: v1
0, v2
1, v3
0, ..... , vn
0
...........................................................................
mapping: v1
0, v2
0, v3
0, ..... , vn
1
The basis {
} is called the basis dual to {
} or the dual basis. There
are infinitely many possible bases for V and each basis has a dual basis as defined above.
See
Hom(V,W). Vector space of all mxn matrices.
Theorem 1. Let {
} be a basis for V and let {
} be the basis of
V* (i.e. dual basis). Then for any vector u
V,
and for any linear functional
V*
Thus we see that the coordinates of u are
and the coordinates of σ
are
.
Annihilator. Let W be a subset (not necessarily a subspace) of a vector space V. A linear
functional
V* is called an annihilator of W if
(w) = 0 for every w
W. The set of all
such mappings, denoted by W0 and called the annihilator of W, is a subspace of V*.
Example. Pass a line through the origin of an x-y-z Cartesian coordinate system and label it L. Let W be the set of all vectors in line L. Pass a plane through the origin of the coordinate system perpendicular to line L and label it K. Let S represent the set of all vectors in plane K. Then S is an annihilator of W. Why? If s is any vector in S and w is any vector in W then the dot product s∙w = 0. The vector s can be viewed as a linear operator (linear functional) mapping the vectors of W into the field of reals and it maps all the elements of W into zero. By the same logic W is an annihilator of S. So the annihilator W0 of W is the set S and the annihilator S0 of the set S is the set W.
Theorem 2. Suppose V has finite dimension and W is a subspace of V. Then
1) dimW + dim W0 = dim V
and
2) W00 = W

Transpose of a linear mapping. Let
T:V
U be an arbitrary linear mapping from
a vector space V into a vector space U. Now
for any linear functional ω ε U*, the
composition mapping ω
T is a linear
mapping from V into F. See Fig. 1. Thus
ω
T ε V*. We thus have a one-to-one
correspondence between ω ε U* and ω
T ε
V*. The linear mapping
T t (ω) = ω
T
that maps ω ε U* into ω
T ε V* is called the transpose of T.
Thus [T t (ω)]v = ω(Tv) for every v ε V.
In summary, if T is a linear mapping from V into U, then T t is a linear mapping from U* into V*:
Theorem 3. Let T:V
U be linear, and let A be the matrix representation of T relative to
bases {vi} of V and {ui} of U. Then the transpose matrix At is the matrix representation of T
t:U*
V* relative to the bases dual to {ui} and {vi}.
References
Lipschutz. Linear Algebra. p. 249-251
Taylor. Introduction to Functional Analysis. p. 33