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THE EXPONENTIAL AND LOGARITHMIC FUNCTIONS, LOGARITHMIC DIFFERENTIATION


Exponents. The process of defining the meaning of an is a multi-step process.


 Step 1. Define the meaning of the symbol an where a is any real number and n is a positive integer as follows:


            a1 = a

            a2 = a • a

            a3 = a • a • a

            .....

            an = a • a • a .... to n factors


This gives us a meaning for an when the exponent n is a positive integer. The following laws are valid for an defined as above (m and n are positive integers):


ole.gif


ole1.gif


ole2.gif


ole3.gif


ole4.gif  


Next we want to give a meaning to such symbols as


             ole5.gif


Our object will be to define these symbols in such a way that laws 1 through 5 will apply in all cases.



Step 2. Assign a meaning to a0. If we want Law 1 to hold so that


 

             ole6.gif


we must assign the value one to the symbol a0.


Def. a0 = 1.



Step 3. Assign a meaning to negative integral exponents. If we wish Law 1 to hold so that

 

            am • a - m = am - m = a0 = 1           (m is an integer, a≠0)


we must agree that a - m = 1/am.


Def. a-m = 1/am where m is an integer.



Def. n-th root. If an = p, where n is a positive integer, we call a an n-th root of p, written ole7.gif There may be more than one real n-th root of p. For example since 22 = 4 and (-2)2 = 4, there are two real square roots of 4, namely 2 and -2.



Step 4. Assign a meaning to fractional exponents. If we wish Law 1 to hold so that


             ole8.gif


we must define the symbol a½ to stand for a square root of a. To avoid ambiguity we can define it to stand for the positive square root. In general, we define the symbol


              ole9.gif  


to stand for the positive q-th root of a.


ole10.gif  



ole11.gif



It follows from these definitions that


             ole12.gif


and that the above five laws are valid if m and n are either fractions or integers (i.e. if they are rational numbers), provided a and b are positive numbers. If the exponent is irrational, the power is defined to be the quantity approximated by using rational exponents which approximate the irrational exponent; e.g. 3 with exponent ole13.gif denotes the limit of the sequence


             ole14.gif



Three important limits.


Theorem 1. If θ is in radians, then


             ole15.gif


Theorem 2. If θ is in radians, then


             ole16.gif


Theorem 3. The number e is given by


             ole17.gif


Logarithms to the base e are called natural logarithms. Loge x is often called log x (base omitted) or ln x.





Def. Exponential function. (1) The function ex.

(2) The function ax, where a is a positive constant. If a ole18.gif 1, the function ax is the inverse of the logarithmic function logax.

                                                James & James. Mathematics Dictionary.


ole19.gif

The exponential function y = ax is shown in Fig. 1. Its derivative is everywhere positive and increases with increasing values of x.

                                                                                                


Def. Logarithmic function y = loga x (a > 1). The logarithmic function is defined as the inverse of the exponential function i.e. if


            x = ay 

                                                                                                

ole20.gif

then


            y = loga x .



See Fig. 2. Its graph is the same as that of y = ax with the axes interchanged. It is defined only for positive values of x.








The derivative of loga u.


Theorem.


             ole21.gif


Proof. We wish to find the derivative of the function


            y = loga x .


We proceed by applying the fundamental differentiation process. Starting at any point P on the curve and letting x increase by an amount Δx we have


             ole22.gif


                         ole23.gif


                         ole24.gif


             ole25.gif


 Let us now multiply numerator and denominator by x giving


             ole26.gif


                         ole27.gif


If now Δx ole28.gif 0, the quantity

 

             ole29.gif

 

approaches the number e because it is of the form


             ole30.gif


with v approaching zero. We have then


             ole31.gif


                         ole32.gif


End of proof.



For the special case of natural logarithms where a = e this becomes


             ole33.gif



If we consider the function y = loga u where u is a differentiable function of x, its derivative with respect to x is given by


             ole34.gif



For the special case of natural logarithms this becomes


             ole35.gif




Example. Find dy/dx for


             ole36.gif



Solution.

             ole37.gif





The derivative of au.


Theorem.


             ole38.gif


Proof. If


            y = ax


then


            x = loga y .


Taking the derivative with respect to y


             ole39.gif


or


             ole40.gif


            = y loge a


            = ax loge a 

 

End of proof.



If u is a differentiable function of x we have


             ole41.gif


If a is the number e, we have


             ole42.gif



Example. Find dy/dx for


             ole43.gif


Solution.


             ole44.gif






Logarithmic differentiation. In obtaining the derivatives of certain kinds of functions, such as complicated products and quotients, and functions of the type uv, where u and v are both variable, it is often easier to take the logarithm before differentiating. This process is called logarithmic differentiation. 


Example 1. Find dy/dx if


             ole45.gif



Solution. Taking logarithms of both sides


            ln y = l ln u + m ln v - n ln w


Differentiating with respect to x


             ole46.gif


Solving for dy/dx


             ole47.gif



Example 2. Find dy/dx if


             ole48.gif


Solution. Taking logarithms of both sides


             ole49.gif


Differentiating with respect to x


             ole50.gif


Solving for dy/dx


             ole51.gif




The derivative of uv. The derivative of a function of the form


            y = uv,


where u and v are differentiable functions of x, can be found by the method of logarithmic differentiation.


Example. Differentiate y = (x + 1)x.


Solution. Taking the natural logarithm of each side, we obtain


            ln y = x ln (x + 1).


Now differentiating this relation implicitly with respect to x we have


             ole52.gif


Solving for dy/dx we get


             ole53.gif


Note that neither the formula for the derivative of un nor the derivative for av applies to functions of this type.

                                                                              


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