THE EXPONENTIAL AND LOGARITHMIC FUNCTIONS, LOGARITHMIC DIFFERENTIATION
Exponents. The process of defining the meaning of an is a multi-step process.
Step 1. Define the meaning of the symbol an where a is any real number and n is a positive integer as follows:
a1 = a
a2 = a a
a3 = a a a
.....
an = a a a .... to n factors
This gives us a meaning for an when the exponent n is a positive integer. The following laws are valid for an defined as above (m and n are positive integers):
Next we want to give a meaning to such symbols as
Our object will be to define these symbols in such a way that laws 1 through 5 will apply in all cases.
Step 2. Assign a meaning to a0. If we want Law 1 to hold so that
we must assign the value one to the symbol a0.
Def. a0 = 1.
Step 3. Assign a meaning to negative exponents. If we wish Law 1 to hold so that
am a - m = am - n = a0 = 1 (a
0)
we must agree that a - m = 1/am.
Def. a-m = 1/am.
Def. n-th root. If an = p, where n is a positive integer, we call a an n-th root of p, written
There may be more than one real n-th root of p. For example since 22 = 4 and (-2)2 = 4, there
are two real square roots of 4, namely 2 and -2.
Step 4. Assign a meaning to fractional exponents. If we wish Law 1 to hold so that
we must define the symbol a½ to stand for a square root of a. To avoid ambiguity we can define it to stand for the positive square root. In general, we define the symbol
to stand for the positive q-th root of a.
It follows from these definitions that
and that the above five laws are valid if m and n are either fractions or integers (i.e. if they are
rational numbers), provided a and b are positive numbers. If the exponent is irrational, the
power is defined to be the quantity approximated by using rational exponents which approximate
the irrational exponent; e.g. 3 with exponent
denotes the limit of the sequence
Three important limits.
Theorem 1. If θ is in radians, then
Theorem 2. If θ is in radians, then
Theorem 3. The number e is given by
Logarithms to the base e are called natural logarithms. Loge x is often called log x (base omitted) or ln x.
Def. Exponential function. (1) The function ex.
(2) The function ax, where a is a positive constant. If a
1, the function ax is the inverse of the
logarithmic function logax.
James & James. Mathematics Dictionary.

The exponential function y = ax is shown in Fig. 1. Its derivative is everywhere positive and increases with increasing values of x.
Def. Logarithmic function y = loga x (a > 1). The logarithmic function is defined as the inverse of the exponential function i.e. if
x = ay

then
y = loga x .
See Fig. 2. Its graph is the same as that of y = ax with the axes interchanged. It is defined only for positive values of x.
The derivative of loga u.
Theorem.
Proof. We wish to find the derivative of the function
y = loga x .
We proceed by applying the fundamental differentiation process. Starting at any point P on the curve and letting x increase by an amount Δx we have
Let us now multiply numerator and denominator by x giving
If now Δx
0, the quantity
approaches the number e because it is of the form
with v approaching zero. We have then
End of proof.
For the special case of natural logarithms where a = e this becomes
If we consider the function y = loga u where u is a differentiable function of x, its derivative with respect to x is given by
For the special case of natural logarithms this becomes
Example. Find dy/dx for
Solution.
The derivative of au.
Theorem.
Proof. If
y = ax
then
x = loga y .
Taking the derivative with respect to y
or
= y loge a
= ax loge a
End of proof.
If u is a differentiable function of x we have
If a is the number e, we have
Example. Find dy/dx for
Solution.
Logarithmic differentiation. In obtaining the derivatives of certain kinds of functions, such as complicated products and quotients, and functions of the type uv, where u and v are both variable, it is often easier to take the logarithm before differentiating. This process is called logarithmic differentiation.
Example 1. Find dy/dx if
Solution. Taking logarithms of both sides
ln y = l ln u + m ln v - n ln w
Differentiating with respect to x
Solving for dy/dx
Example 2. Find dy/dx if
Solution. Taking logarithms of both sides
Differentiating with respect to x
Solving for dy/dx
The derivative of uv. The derivative of a function of the form
y = uv,
where u and v are differentiable functions of x, can be found by the method of logarithmic differentiation.
Example. Differentiate y = (x + 1)x.
Solution. Taking the natural logarithm of each side, we obtain
ln y = x ln (x + 1).
Now differentiating this relation implicitly with respect to x we have
Solving for dy/dx we get
Note that neither the formula for the derivative of un nor the derivative for av applies to functions of this type.